Soal Logaritma 1

Posted: October 22, 2010 in logaritma, matematika

jika 3^{a} = 4 , 4^{b} = 5 , 5^{c} = 6 ,6^{d} = 7 , 7^{e} = 8 , 8^{f} = 9
berapakah nilai a.b.c.d.e.f ?

sesuai judul nya tentu ini menggunakan logartima
ingat lah sifat logaritma yg paling dasar 3^{a} = 4 adalah ^{3}log4=a
semua nya juga di ubah
sehingga:
a.b.c.d.e.f = ^{3}log4 . ^{4}log5 . ^{5}log6 . ^{6}log7 . ^{7}log8 . ^{8}log9.
bisa di coret sehingga sisa
a.b.c.d.e.f = ^{3}log9
a.b.c.d.e.f = 2

simple kan ?
selesai

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